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Home » The solution is \(\boxed12\). - iBuildNew

The solution is \(\boxed12\). - iBuildNew

📅 April 30, 2026 👤 scraface

Apr 30, 2026

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\sin 315^\circ = -\sin 45^\circ = -\frac{\sqrt{2}}{2}
Thus, the value is:
\boxed{-\frac{\sqrt{2}}{2}}
Question:** The sides of a triangle are 9, 40, and 41 units. Find the...
First, verify the triangle is right-angled:
9^2 + 40^2 = 81 + 1600 = 1681 = 41^2
So it is a right triangle with legs 9 and 40, hypotenuse 41. The area...
A = \frac{1}{2} \times 9 \times 40 = 180 \text{ units}^2
The altitudes corresponding to each side are:
To side 9: \(h_9 = \frac{2A}{9} = \frac{360}{9} = 40\)

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