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Rounded to nearest person: 3002 - iBuildNew

📅 April 29, 2026 👤 scraface

Apr 29, 2026

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We want to maximize x, so minimize y. Try x = 20:
So maximum x such that energy and budget are met is not feasible? Wait...
Try x = 10, y = 20: energy = 2000 + 4500 = 6500 < 16,200 — too low.
Try x = 20, y = 10: energy = 4500 + 3200 = 7700, cost = 62,000 + 31,00...
Try x = 15, y = 15: energy = 6750 + 6750 = 13,500 < 16,200.
x = 25, y = 5: energy = 11,250 + 2,250 = 13,500 < 16,200.
x = 30, y = 5: energy = 13,500 + 2,250 = 15,750 < 16,200.
Try x = 15, y = 20: energy = 4500 + 6000 = 10,500 < 16,200.
It appears no combination satisfies both. But lets solve system:
So use as much B as possible within budget.

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