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ight) \Rightarrow (x \mid 0) - iBuildNew

📅 April 30, 2026 👤 scraface

Apr 30, 2026

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Combine: $(-\omega -2\omega + \omega) = -2\omega$, $(-3 + 2 + 5) = 4$...
So $a = -2$, $b = 4$
But let's verify with another point or use polynomial identity.
Let $D(x) = x^4 + 3x^3 - 2x^2 + x + 5$, $D(x) = (x^2 - x + 1)(x^2 + ax...
Compute RHS:
$(x^2 - x + 1)(x^2 + ax + b) = x^4 + ax^3 + bx^2 - x^3 - ax^2 - bx + x...
Add $-2x + 4$:
$x^4 + (a-1)x^3 + (b-a+1)x^2 + (a-b - 2)x + (b + 4
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