VARA200

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Since no integer solution, but in real context, perhaps accept \( n = 14 \) as closest? But not exact.
Wait — perhaps I miscalculated the sum formula.
General: \( S_n = \frac{n}{2}[2a + (n-1)d] = \frac{n}{2}[6 + (n-1)2] = \frac{n}{2}(2n + 4) = n(n + 2) \). Correct.

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